567x^2-28=0

Solution for 567x^2-28=0 equation:

567x^2-28=0

a = 567; b = 0; c = -28;
Δ = b2-4ac
Δ = 02-4·567·(-28)
Δ = 63504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{63504}=252$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-252}{2*567}=\frac{-252}{1134}
=-2/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+252}{2*567}=\frac{252}{1134}
=2/9
$